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The pressure exerted by an electromagnetic wave of intensity $I$ on a non-reflecting surface is [where $c$ is the speed of light]

1. $\frac{I}{c}$
2. $\frac{2I}{c}$
3. $Ic$
4. $\frac{c}{I}$

Correct answer: $\frac{I}{c}$

Solution

For a non-reflecting (perfectly absorbing) surface, the radiation pressure is $p = I/c$. Reflection would double the pressure, but that is not the case here.

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