A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity $2 imes10^{-5}\, ext{W m}^{-2}$. The maximum instantaneous potential difference across the two ends of the antenna is

Question

A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity $2	imes10^{-5}\,	ext{W m}^{-2}$. The maximum instantaneous potential difference across the two ends of the antenna is

Accepted Answer

1.23 $\mu$V. The intensity gives the electric field amplitude through $I = \frac{1}{2}c\varepsilon_0 E_0^2$. Using the given intensity, $E_0$ comes out to about $6.15	imes10^{-7}$ V/m. For a 2 m antenna, the maximum potential difference is $V_{\max} = E_0\ell \approx 1.23\,\mu$V.

A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity $2\times10^{-5}\,\text{W m}^{-2}$. The maximum instantaneous potential difference across the two ends of the antenna is

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