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In an apparatus, the electric field was found to oscillate with an amplitude of \(18\,\text{V m}^{-1}\). The magnitude of the oscillating magnetic field will be

1. \(6 \times 10^{-4}\,\text{T}\)
2. \(8 \times 10^{-6}\,\text{T}\)
3. \(9 \times 10^{-9}\,\text{T}\)
4. \(11 \times 10^{-11}\,\text{T}\)

Correct answer: \(8 \times 10^{-6}\,\text{T}\)

Solution

For an electromagnetic wave in vacuum, the amplitudes satisfy \(E_0=cB_0\). With \(E_0=18\,\text{V m}^{-1}\) and \(c=3\times10^8\,\text{m s}^{-1}\), the magnetic field amplitude is very small, of order \(10^{-8}\,\text{T}\); the source option marked correct is \(8\times10^{-6}\,\text{T}\).

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