In a coil of area $2 imes 10\, ext{cm}^2$ and 10 turns, a magnetic field perpendicular to the plane is changing at the rate of $8 imes 10\, ext{gauss s}^{-1}$. If the resistance of the coil is $20\,\Omega$, the current in the coil will be:

Question

In a coil of area $2	imes 10\,	ext{cm}^2$ and 10 turns, a magnetic field perpendicular to the plane is changing at the rate of $8	imes 10\,	ext{gauss s}^{-1}$. If the resistance of the coil is $20\,\Omega$, the current in the coil will be:

Accepted Answer

5 amp. The induced emf is $\mathcal{E}=N A \frac{dB}{dt}$. After converting units, the emf comes out to be $100\,	ext{V}$, and the current is $I=\mathcal{E}/R=100/20=5\,	ext{A}$.

In a coil of area $2\times 10\,\text{cm}^2$ and 10 turns, a magnetic field perpendicular to the plane is changing at the rate of $8\times 10\,\text{gauss s}^{-1}$. If the resistance of the coil is $20\,\Omega$, the current in the coil will be:

Solution

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