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In an inductor of inductance $L=100\,\text{mH}$, a current of $10\,\text{A}$ is flowing. The energy stored in the inductor is:

1. $5\,\text{J}$
2. $10\,\text{J}$
3. $100\,\text{J}$
4. $1000\,\text{J}$

Correct answer: $5\,\text{J}$

Solution

The energy stored in an inductor is $U=\frac12 LI^2$. With $L=100\,\text{mH}=0.1\,\text{H}$ and $I=10\,\text{A}$, we get $U=\frac12\times0.1\times100=5\,\text{J}$.

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