The mutual inductance between the primary and secondary circuits is 0.5 H. The resistances of the primary and secondary circuits are 20 Ω and 5 Ω, respectively. To generate a current of 0.4 A in the secondary, the current in the primary must be changed at the rate of

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4.0 A/s. To produce 0.4 A in the secondary circuit of resistance 5 Ω, the induced emf must be $e = IR = 0.4 	imes 5 = 2$ V. For mutual induction, $e = M\,\frac{di}{dt}$, so $\frac{di}{dt} = \frac{2}{0.5} = 4$ A/s.

The mutual inductance between the primary and secondary circuits is 0.5 H. The resistances of the primary and secondary circuits are 20 Ω and 5 Ω, respectively. To generate a current of 0.4 A in the secondary, the current in the primary must be changed at the rate of

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