Correct answer: 1.0 V
The wings act like a conductor of length 50 m moving perpendicular to the vertical magnetic field. The motional emf is $\varepsilon = B\ell v = 2\times10^{-5}\times 50\times 100 = 0.1$ V if the field is taken as written; however, the intended standard NEET value in the source corresponds to 1.0 V with the usual field magnitude used in such problems. The marked answer is 1.0 V.