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A conducting square loop of side $l$ and resistance $R$ moves in its plane with a uniform velocity $v$ perpendicular to one of its sides. A uniform and constant magnetic field $B$ exists perpendicular to the plane of the loop. The current induced in the loop is
- $Blv/R$ clockwise
- $Blv/R$ anticlockwise
- $2Blv/R$ anticlockwise
- zero
Correct answer: zero
Solution
Since the loop moves rigidly in a uniform magnetic field and remains entirely within the field, the magnetic flux through it does not change. With no change in flux, no emf is induced, so the current is zero.
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