The figure represents an area $A=0.5\, ext{m}^2$ situated in a uniform magnetic field $B=2.0\, ext{Wb m}^{-2}$ and making an angle of $60^\circ$ with respect to the magnetic field. The magnetic flux through the area is equal to

Question

The figure represents an area $A=0.5\,	ext{m}^2$ situated in a uniform magnetic field $B=2.0\,	ext{Wb m}^{-2}$ and making an angle of $60^\circ$ with respect to the magnetic field. The magnetic flux through the area is equal to

Accepted Answer

0.5 weber. Magnetic flux through a surface is $\Phi=BA\cos	heta$, where $	heta$ is the angle between the magnetic field and the area vector (normal to the surface). With $B=2.0\,	ext{Wb m}^{-2}$ and $A=0.5\,	ext{m}^2$, the flux is $2.0	imes0.5	imes\cos 60^\circ=0.5\,	ext{Wb}$.

The figure represents an area $A=0.5\,\text{m}^2$ situated in a uniform magnetic field $B=2.0\,\text{Wb m}^{-2}$ and making an angle of $60^\circ$ with respect to the magnetic field. The magnetic flux through the area is equal to

Solution

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