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A coil having 500 square loops, each of side 10 cm, is placed normal to a magnetic flux that increases at the rate of 1.0 tesla per second. The induced emf in volts is
- 0.1
- 0.5
- 1
- 5
Correct answer: 5
Solution
For a coil normal to the magnetic field, induced emf is $\mathcal{E}=N A \frac{dB}{dt}$. Here $N=500$, $A=(0.1)^2=0.01\,\text{m}^2$, and $\frac{dB}{dt}=1\,\text{T s}^{-1}$, so $\mathcal{E}=500\times0.01\times1=5\,\text{V}$.
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