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The magnetic flux linked with a coil is given by \(\phi\) (in webers) = \(5 + 3t + 8t^2\). The induced e.m.f. in the coil at the fourth second will be
- 16 units
- 39 units
- 67 units
- 145 units
Correct answer: 67 units
Solution
By Faraday’s law, induced emf is \(e = -\frac{d\phi}{dt}\). For \(\phi = 5 + 3t + 8t^2\), we get \(\frac{d\phi}{dt} = 3 + 16t\). At \(t=4\,\text{s}\), this becomes \(3 + 64 = 67\), so the magnitude of emf is 67 units.
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