Given $\vec a + \vec b + \vec c = 0$. Out of the three vectors $\vec a$, $\vec b$, and $\vec c$, two are equal in magnitude. The magnitude of the third vector is 2 times that of either of the two having equal magnitude. The angles between the vectors are:

Question

Accepted Answer

90°, 135°, 135°. Since $\vec a+\vec b+\vec c=0$, the three vectors form a closed triangle when placed head-to-tail. If two vectors have equal magnitude and the third is twice either of them, the triangle is a right isosceles triangle, giving angles 90°, 135°, and 135° between the vectors.

Given \(\vec a + \vec b + \vec c = 0\). Out of the three vectors \(\vec a\), \(\vec b\), and \(\vec c\), two are equal in magnitude. The magnitude of the third vector is 2 times that of either of the two having equal magnitude. The angles between the vectors are:

Solution

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