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ExamsNEETPhysics

The roots of the equation $2x^2+5x-12=0$ are:

  1. $\frac{3}{2},\,-4$
  2. $\frac{2}{3},\,-4$
  3. $\frac{3}{2},\,4$
  4. $\frac{2}{3},\,4$

Correct answer: $\frac{3}{2},\,-4$

Solution

Factorizing, $2x^2+5x-12=(2x-3)(x+4)=0$. Hence the roots are $x=\frac{3}{2}$ and $x=-4$.

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