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A bar magnet is dropped along the axis of copper ring held horizontally. The acceleration of fall is

1. equal to g at the place.
2. less than \( g \)
3. more than \( g \)
4. depends upon diameter of the ring and length of the magnet

Correct answer: less than \( g \)

Solution

As the magnet falls through the copper ring, the changing flux induces currents in the ring. By Lenz’s law, the magnetic field due to these currents opposes the magnet’s downward motion, so the net downward force is reduced and the acceleration is less than g.

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