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Water is filled upto same height in two identical closed containers \( A \) and \( B \). Container \( A \) has vacuum over the water while container \( B \) has air over the water. At the same depth of both the containers there is an opening on which identical balloons \( A \) and \( B \) are attached as shown in the figure given below. Then

1. Balloon - \( A \) will bulge more than balloon - \( B \)
2. Balloon - \( B \) will bulge more than balloon - \( A \)
3. Both the balloons will bulge equally
4. None of the balloons will bulge

Correct answer: Balloon - \( B \) will bulge more than balloon - \( A \)

Solution

At the same depth, the pressure at the opening equals the pressure on the water surface plus the hydrostatic term \(\rho gh\). Container A has vacuum above the water, so its opening pressure is lower. Container B has air above the water, so its opening pressure is higher, making balloon B bulge more.

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