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If D = 2m, d = 1mm (1 × 10⁻³ m), and λ = 600nm (600 × 10⁻⁹ m), determine the total width of the central bright fringe (2β).
- 2β = 1mm
- 2β = 2mm
- 2β = 3mm
- 2β = 4mm
Correct answer: 2β = 2mm
Solution
The width of the central bright fringe is given by 2β = 2λD/d. Substituting the values: 2 × (600 × 10⁻⁹) × 2 / (1 × 10⁻³) = 2 × 10⁻³ m = 2 mm.
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