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Determine the phase difference ϕ when the path difference AP - BP equals λ for the first minimum at point P.
- ϕ equals π radians
- ϕ equals 2π radians
- ϕ equals π/2 radians
- ϕ equals 3π/2 radians
Correct answer: ϕ equals π radians
Solution
For the first minima in an interference pattern, the path difference is equal to one wavelength (λ). The corresponding phase difference is given by ϕ = 2π × (path difference/λ). Substituting path difference = λ, we get ϕ = 2π × (λ/λ) = π radians.
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