At point A, the relationship is given as $ a \mu_g = \frac{\sin 45^\circ}{\sin r} $ and $ \sin r = \frac{1}{\sqrt{2} a \mu_g} $. At point B, the critical angle $ (90^\circ - r) $ satisfies $ \sin (90^\circ - r) = g \mu_a $. Which of the following is correct?

Question

Accepted Answer

$ \cos r = g \mu_a $. From the given equations, we know that $ \sin(90^\circ - r) = \cos r $. Substituting $ g \mu_a $ for $ \sin(90^\circ - r) $, we get $ \cos r = g \mu_a $, which matches option A.

At point A, the relationship is given as \( a \mu_g = \frac{\sin 45^\circ}{\sin r} \) and \( \sin r = \frac{1}{\sqrt{2} a \mu_g} \). At point B, the critical angle \( (90^\circ - r) \) satisfies \( \sin (90^\circ - r) = g \mu_a \). Which of the following is correct?

Solution

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