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The momentum of a photon of an electromagnetic radiation is 3.3 × 10⁻²⁹ kgms⁻¹. What is the frequency of the associated waves? [h = 6.6 × 10⁻³⁴ Js; c = 3 × 10⁸ ms⁻¹]
- 1.5 × 10¹³ Hz
- 7.5 × 10¹² Hz
- 6.0 × 10¹³ Hz
- 3.0 × 10³ Hz
Correct answer: 1.5 × 10¹³ Hz
Solution
The momentum of a photon is given by p = h/λ, and λ = c/f. Substituting λ = c/f into p = h/λ gives p = hf/c. Rearranging for f, we get f = pc/h. Substituting p = 3.3 × 10⁻²⁹ kgms⁻¹, h = 6.6 × 10⁻³⁴ Js, and c = 3 × 10⁸ ms⁻¹, we find f = (3.3 × 10⁻²⁹ × 3 × 10⁸) / (6.6 × 10⁻³⁴) = 1.5 × 10¹³ Hz.
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