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The photoelectric threshold wavelength of silver is 3250 × 10⁻¹⁰ m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536 × 10⁻¹⁰ m is (Given h = 4.14 × 10⁻¹⁵ eVs and c = 3 × 10⁸ m/s)
- ≈ 0.6 × 10⁶ m/s
- ≈ 6.1 × 10⁶ m/s
- ≈ 0.3 × 10⁶ m/s
- ≈ 6 × 10⁵ m/s
Correct answer: ≈ 6.1 × 10⁶ m/s
Solution
The energy of the incident photon is calculated using E = hc/λ. The work function is found using the threshold wavelength. The kinetic energy of the ejected electron is the difference between the photon energy and the work function. Using KE = 0.5mv², the velocity is calculated to be approximately 6.1 × 10⁶ m/s.
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