Exams › NEET › Physics

Angular limit of resolution of eye, θ = λ/d, where d is diameter of eye lens. Also, if Y is the minimum separation between two objects at distance D from eye then:

1. Y = λD/d
2. Y = λ/dD
3. Y = d/λD
4. Y = D/λd

Correct answer: Y = λD/d

Solution

The angular limit of resolution is given as θ = λ/d. For small angles, θ ≈ Y/D, where Y is the minimum separation and D is the distance. Substituting θ = λ/d into θ ≈ Y/D gives Y = λD/d.

Related NEET Physics questions

• An image formed by a plane mirror is:
• One face of a rectangular glass plate 6 cm thick is silvered. An object held 8 cm in front of the first face forms an image 12 cm behind the silvered face. The refractive index of the glass is
• Time taken by sunlight to pass through a window of thickness 4 mm whose refractive index is 3/2 is
• A beam of monochromatic light is refracted from vacuum into a medium of refractive index 1.5, the wavelength of refracted light will be
• Green light of wavelength 5460 Å is incident on an air-glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be (c = 3 × 10⁸ ms⁻¹)
• When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid, it acts as a plane sheet of glass. This implies that the liquid must have refractive index.

⚔️ Practice NEET Physics free + battle 1v1 →