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Distance of nth maxima, x = nλD/d ∝ λ. As λb < λg, xblue < xgreen. Fringes with red light are thicker than those for blue light.

1. λred > λblue
2. λred < λblue
3. xblue > xgreen
4. xblue < xgreen

Correct answer: λred > λblue

Solution

The fringe width is directly proportional to the wavelength (λ). Since red light has a longer wavelength than blue light (λred > λblue), the fringes for red light are thicker than those for blue light.

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