A parallel beam of monochromatic light of wavelength 5000 Å is incident normally on a single narrow slit of width 0.001 mm. The light is focussed by a convex lens on a screen placed in focal plane. The first minimum will be formed for the angle of diffraction equal to:

Question

Accepted Answer

15°. The condition for the first minimum in single-slit diffraction is given by the equation a*sin(θ) = λ, where 'a' is the slit width and 'λ' is the wavelength. Substituting a = 0.001 mm = 10⁻⁶ m and λ = 5000 Å = 5 × 10⁻⁷ m, we get sin(θ) = λ/a = 0.5, which corresponds to θ = 30°.

A parallel beam of monochromatic light of wavelength 5000 Å is incident normally on a single narrow slit of width 0.001 mm. The light is focussed by a convex lens on a screen placed in focal plane. The first minimum will be formed for the angle of diffraction equal to:

Solution

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