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ExamsNEETPhysics

A beam of light of λ = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is:

  1. 1.2 cm
  2. 1.2 mm
  3. 2.4 cm
  4. 2.4 mm

Correct answer: 2.4 cm

Solution

The angular position of the first dark fringe in single-slit diffraction is given by the condition a*sin(θ) = mλ, where m = ±1 for the first dark fringes. For small angles, sin(θ) ≈ tan(θ) ≈ y/D, where y is the fringe position on the screen and D is the distance to the screen. Substituting values, the total distance between the first dark fringes on either side is 2y = 2(λD/a) = 2(600 × 10⁻⁹ × 2 / 1 × 10⁻³) = 2.4 × 10⁻² m = 2.4 cm.

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