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In a diffraction pattern due to a single slit of width 'a', the first minimum is observed at an angle 30° when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of
- sin⁻¹(1/4)
- sin⁻¹(2/3)
- sin⁻¹(1/2)
- sin⁻¹(3/4)
Correct answer: sin⁻¹(1/4)
Solution
The condition for the first minimum in single-slit diffraction is a * sin(θ) = mλ, where m = 1. For the first secondary maximum, the condition is approximately a * sin(θ) = (3/2)λ. Using the given data, a * sin(30°) = λ, so a = 2λ. Substituting into the secondary maximum condition, sin(θ) = (3/4).
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