For a parallel beam of monochromatic light of wavelength 'λ', diffraction is produced by a single slit whose width 'a' is of the wavelength of the light. If 'D' is the distance of the screen from the slit, the width of the central maxima will be:

Question

Accepted Answer

2Dλ/a. The angular width of the central maximum in single-slit diffraction is given by 2λ/a. Multiplying this by the distance to the screen, D, gives the linear width as 2Dλ/a.

For a parallel beam of monochromatic light of wavelength 'λ', diffraction is produced by a single slit whose width 'a' is of the wavelength of the light. If 'D' is the distance of the screen from the slit, the width of the central maxima will be:

Solution

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