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In Young’s experiment, two coherent sources are placed 0.90 mm apart and fringe are observed on a screen 1 m away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would be
- 60 × 10⁻⁴ cm
- 10 × 10⁻⁴ cm
- 10 × 10⁻⁵ cm
- 6 × 10⁻⁵ cm
Correct answer: 6 × 10⁻⁵ cm
Solution
The position of the nth dark fringe in Young's double-slit experiment is given by y = (n + 0.5)λD/d. For the second dark fringe (n = 2), y = 1 mm, D = 1 m, and d = 0.90 mm. Substituting these values and solving for λ gives λ = 6 × 10⁻⁵ cm.
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