Exams › NEET › Physics

In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width:

1. is doubled
2. is halved
3. becomes four times
4. remains unchanged

Correct answer: becomes four times

Solution

The fringe width in Young's double-slit experiment is given by the formula β = λD/d, where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the separation between the slits. If D is doubled and d is halved, the fringe width becomes four times larger because β ∝ D/d.

Related NEET Physics questions

• Ray optics is valid when characteristic dimension are
• In Young's experiment with white light, the central fringe is white. If now a transparent film is introduced in the upper beam coming from the top slit, then the white fringe:
• A: Coloured spectrum is seen when we look through a cloth R: Diffraction of light takes place when light is travelling through the pores of cloth
• A microscope is used with sodium light and its resolving power is not sufficiently large.Higher resolution will be obtained by using wavelength of
• Assertion Assertion: When a light wave travels from a rarer to a denser medium, its speed decreases. The decrease in speed imply a reduction in energy carried by the light wave. Reason Reason: The energy of a wave is inversely proportional to velocity of wave
• When light travels from one medium into another it suffers

⚔️ Practice NEET Physics free + battle 1v1 →