StreakPeaked· Practice

ExamsNEETPhysics

In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference

  1. 11 λ/2
  2. 5 λ/2
  3. λ/2
  4. 9 λ/2

Correct answer: 9 λ/2

Solution

In a Young's double-slit experiment, the condition for a minimum is that the path difference is an odd multiple of λ/2. For the fifth minimum, the path difference is (2n+1)λ/2, where n=4 (since n starts from 0). Substituting n=4 gives (2×4+1)λ/2 = 9λ/2.

Related NEET Physics questions

⚔️ Practice NEET Physics free + battle 1v1 →