Exams › NEET › Physics

In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, the fringe width becomes:

1. half
2. four times
3. one-fourth
4. double

Correct answer: four times

Solution

The fringe width in Young's double slit experiment is given by β = λD/d, where λ is the wavelength, D is the distance between the slits and the screen, and d is the separation between the slits. If d is halved and D is doubled, β becomes 4 times its original value.

Related NEET Physics questions

• Ray optics is valid when characteristic dimension are
• In Young's experiment with white light, the central fringe is white. If now a transparent film is introduced in the upper beam coming from the top slit, then the white fringe:
• A: Coloured spectrum is seen when we look through a cloth R: Diffraction of light takes place when light is travelling through the pores of cloth
• A microscope is used with sodium light and its resolving power is not sufficiently large.Higher resolution will be obtained by using wavelength of
• Assertion Assertion: When a light wave travels from a rarer to a denser medium, its speed decreases. The decrease in speed imply a reduction in energy carried by the light wave. Reason Reason: The energy of a wave is inversely proportional to velocity of wave
• When light travels from one medium into another it suffers

⚔️ Practice NEET Physics free + battle 1v1 →