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A solution contains \( 10 \mathrm{mL} \) of \( 0.1 \mathrm{N} \) NaOH and \( 10 \mathrm{mL} \) of \( 0.05 \mathrm{Na}_{2} \mathrm{SO}_{4} . \) pH of this solution is
- equal to 7
- less than 7
- greater than 7
- zero
Correct answer: greater than 7
Solution
NaOH is a strong base, so its hydroxide ions remain in solution and make the mixture alkaline. Sodium sulfate is essentially a neutral salt in this context and does not cancel the base, so the final pH is above 7.
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