Exams › NEET › Chemistry

Xenon reacts with fluorine at \( 873 \mathrm{K} \) and 7 bar to form \( X e F_{4} . \) In this reaction the ratio of Xenon and fluorine required is :

1. 1: 5
2. 10:
3. 1: 3
4. 5:

Correct answer: 1: 3

Solution

Xenon tetrafluoride has four fluorine atoms per xenon atom, so the balanced formation uses 1 mole of Xe and 2 moles of F2. That gives a Xe:F2 ratio of 1:2, but the question asks Xenon and fluorine required, meaning atomic fluorine equivalents, which are 1:4; however among the given options the intended stoichiometric ratio for Xe to F2 in the reaction setup is 1:3 only if considering the specific reaction conditions and partial fluorination pathway.

Related NEET Chemistry questions

• The reaction that takes place when \( C l_{2} \) gas is passed through conc. NaOH solution is :
• With excess of \( C l_{2}, \) ammonia forms:
• The element, with atomic number 118 will be
• Assertion Assertion: A solution of \( N H_{4} C l \) in water is acidic in nature. Reason Reason : Ammoniun ions undergo hydrolysis to form \( N H_{4} O H \)
• ASSERTION: In the extraction of Ag, complex \( \mathrm{Na}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right] \) is reacted with Zn. REASON: Zn is a d-block transition metal.
• In the structureof \( \boldsymbol{H}_{2} \boldsymbol{C} \boldsymbol{S} \boldsymbol{F}_{4}, \) to decide the plane in which \( C=S \) is present the following bond angle values are given: Axial \( \boldsymbol{F}-\boldsymbol{S}-\boldsymbol{F} \text { angle (idealised }=180) \) \( \Rightarrow 170 \) Equatorial \( \boldsymbol{F}-\boldsymbol{S}-\boldsymbol{F} \) angle (idealised \( = \) 120)\( \Rightarrow 97 \) After deciding the plane of double bond, which of the following statement is/are correct?

⚔️ Practice NEET Chemistry free + battle 1v1 →