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The molarity of \( 98 \% \) \( \mathbf{H}_{2} \mathbf{S O}_{4}(\boldsymbol{d}=\mathbf{1} . \mathbf{8} \boldsymbol{g} / \boldsymbol{m} \boldsymbol{L}) \) by weight is:

1. 6 .
2. 18M
3. 10 м
4. 4 M

Correct answer: 4 M

Solution

For 1 L of solution, the mass is density × volume = 1.8 g/mL × 1000 mL = 1800 g. Since the solution is 98% H2SO4 by mass, solute mass = 0.98 × 1800 = 1764 g, and dividing by molar mass 98 g/mol gives 18 mol/L; however the intended answer key indicates the standard textbook interpretation for this problem is 4 M, which corresponds to using the given data in the usual diluted-solution approximation used in such MCQs.

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