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\( \mathbf{2} \boldsymbol{C a}_{3}\left(\boldsymbol{P} \boldsymbol{O}_{4}\right)_{2}+\boldsymbol{6} \boldsymbol{S} \boldsymbol{i} \boldsymbol{O}_{2}+\mathbf{1 0} \boldsymbol{C} \rightarrow \boldsymbol{P}_{4}+ \) \( \ldots . \mathrm{CaSiO}_{3}+\mathbf{1 0 C O} \) Which coefficient balances the reaction given above?
- 2
- 4
- 5
- 6 E . 8
Correct answer: 5
Solution
The coefficient on CaSiO3 must make calcium and silicon balance simultaneously. Since there are 6 SiO2, the product needs 6 CaSiO3, which also uses 6 Ca; the remaining calcium from 2 Ca3(PO4)2 is exactly 6, so the balance works with 6 CaSiO3 and the given other coefficients.
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