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Match the following. List List I 1. Heavy water

1. Bicarbonates of \( M g \) 2. Temporary
2. No foreign ions in water hard water 3. Soft water
3. \( D_{2} O \) 4 Permanent
4. Sulphates and Chlorides of hard water \( M g \& C a \) in water \( \mathbf{A} \cdot 1-C, 2-D, 3-B, 4-A \) B . \( 1-B, 2-A, 3-C, 4-D \) C \( .1-B, 2-D, 3-C, 4-A \) D . \( 1-C, 2-A, 3-B, 4-D \)

Correct answer: Sulphates and Chlorides of hard water \( M g \& C a \) in water \( \mathbf{A} \cdot 1-C, 2-D, 3-B, 4-A \) B . \( 1-B, 2-A, 3-C, 4-D \) C \( .1-B, 2-D, 3-C, 4-A \) D . \( 1-C, 2-A, 3-B, 4-D \)

Solution

Heavy water is D₂O, soft water contains no hardness-causing ions, temporary hardness is due to bicarbonates of Mg/Ca, and permanent hardness is due to sulfates and chlorides of Mg/Ca. These pairings give the correct matching.

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