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HI cannot be prepared by the action of conc. \( \boldsymbol{H}_{2} \boldsymbol{S} \boldsymbol{O}_{4} \) on \( \mathrm{K} \) I because \( \boldsymbol{H}_{2} \boldsymbol{S} \boldsymbol{O}_{4} \) is \( -? \)

1. oxidising agent
2. reducing agent
3. A and B
4. None of these

Correct answer: oxidising agent

Solution

Concentrated H2SO4 is an oxidising agent, so it oxidizes I−/HI to iodine while itself being reduced. Because HI gets converted, it cannot be prepared by simply treating KI with conc. sulfuric acid.

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