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Choose the incorrect statements. This question has multiple correct options

1. All \( S-F \) bond lengths are identical in \( S F_{4} \)
2. All \( C l-F \) bond lengths are identical in \( C l F_{3} \)
3. All \( \angle F C l F \) angles are not identical in \( C l F_{3} \)
4. All possible angle in \( B F_{2} C l \) are \( 120^{\circ} \)

Correct answer: All \( S-F \) bond lengths are identical in \( S F_{4} \)

Solution

In SF4, the seesaw shape makes axial and equatorial S–F bonds inequivalent, so their bond lengths are not all the same. The other statements are consistent with the expected geometries: ClF3 has nonidentical F–Cl–F angles, and BF2Cl is trigonal planar with 120° angles.

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