Exams › NEET › Chemistry

Trisilylamine \( \left[\ddot{\boldsymbol{N}}\left(\boldsymbol{S} \boldsymbol{i} \boldsymbol{H}_{3}\right)_{3}\right] \) has \( \mathbf{a} \)

1. planer geometry
2. tetrahedral geometry
3. pyramidal geometry
4. none of these

Correct answer: pyramidal geometry

Solution

In trisilylamine, the nitrogen atom has three sigma bonds and one lone pair, giving four electron domains. VSEPR predicts a trigonal pyramidal molecular geometry for this arrangement.

Related NEET Chemistry questions

• The reaction that takes place when \( C l_{2} \) gas is passed through conc. NaOH solution is :
• With excess of \( C l_{2}, \) ammonia forms:
• The element, with atomic number 118 will be
• Assertion Assertion: A solution of \( N H_{4} C l \) in water is acidic in nature. Reason Reason : Ammoniun ions undergo hydrolysis to form \( N H_{4} O H \)
• ASSERTION: In the extraction of Ag, complex \( \mathrm{Na}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right] \) is reacted with Zn. REASON: Zn is a d-block transition metal.
• In the structureof \( \boldsymbol{H}_{2} \boldsymbol{C} \boldsymbol{S} \boldsymbol{F}_{4}, \) to decide the plane in which \( C=S \) is present the following bond angle values are given: Axial \( \boldsymbol{F}-\boldsymbol{S}-\boldsymbol{F} \text { angle (idealised }=180) \) \( \Rightarrow 170 \) Equatorial \( \boldsymbol{F}-\boldsymbol{S}-\boldsymbol{F} \) angle (idealised \( = \) 120)\( \Rightarrow 97 \) After deciding the plane of double bond, which of the following statement is/are correct?

⚔️ Practice NEET Chemistry free + battle 1v1 →