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toppr Q Type your question_ \( 4+3 \cup+1 \) 木 b. \( \left(\boldsymbol{C H}_{3}\right)_{2} \boldsymbol{C}=\boldsymbol{C H}_{2}+\boldsymbol{H C l} \rightarrow \) \( \left(\boldsymbol{C H}_{3}\right)_{2}(\boldsymbol{C l}) \boldsymbol{C}-\boldsymbol{C H}_{3} \) c. \( \left(\boldsymbol{C H}_{3}\right)_{3} \boldsymbol{C}-\boldsymbol{C H}_{2} \boldsymbol{O H}+\boldsymbol{H} \boldsymbol{B r} \rightarrow \) \( \left(\boldsymbol{C H}_{3}\right)_{2} \boldsymbol{C}(\boldsymbol{B r}) \boldsymbol{C H}_{2} \boldsymbol{C H}_{3} \) d. \( \boldsymbol{C H}_{3} \boldsymbol{C H}_{2} \boldsymbol{B r}+\boldsymbol{H O}^{\ominus} \rightarrow \boldsymbol{C H}_{2}= \) \( \boldsymbol{C H}_{2} \)
- a.Nucleophilic substitution and 1, 2-Methyl shift
- Nucleophilic substitution reaction
- Elimination reaction
- Addition reaction B. a.Addition reaction b. Nucleophilic substitution reaction c. Elimination reaction d. Nucleophilic substitution and 1, 2-Methyl shift c. a. Nucleophilic substitution reaction b. Addition reaction c. Nucleophilic substitution and 1, 2-Methyl shift d. Elimination reaction D. a.Addition reaction b. Nucleophilic substitution reaction c. Nucleophilic substitution and 1, 2-Methyl shift d. Elimination reaction
Correct answer: Addition reaction B. a.Addition reaction b. Nucleophilic substitution reaction c. Elimination reaction d. Nucleophilic substitution and 1, 2-Methyl shift c. a. Nucleophilic substitution reaction b. Addition reaction c. Nucleophilic substitution and 1, 2-Methyl shift d. Elimination reaction D. a.Addition reaction b. Nucleophilic substitution reaction c. Nucleophilic substitution and 1, 2-Methyl shift d. Elimination reaction
Solution
The correct option matches the reaction types for each equation: (a) is addition across a multiple bond, (b) is nucleophilic substitution, (c) involves substitution with rearrangement via a 1,2-methyl shift, and (d) is elimination to form an alkene. So the set of classifications in option D is the right one.
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