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The correct order of decreasing acidity of nitrophenols will be:
- \( m- \) nitrophenol \( >p- \) nitrophenol \( >o \) - nitrophenol
- \( o \) - nitrophenol \( >m- \) nitrophenol \( >p- \) nitrophenol
- \( p- \) nitrophenol \( >m- \) nitrophenol \( >o- \) nitrophenol
- \( p- \) nitrophenol \( >o \) - nitrophenol \( >m- \) nitrophenol
Correct answer: \( o \) - nitrophenol \( >m- \) nitrophenol \( >p- \) nitrophenol
Solution
Ortho-nitrophenol is most acidic because the nitro group strongly withdraws electron density and can stabilize the conjugate base effectively. Meta lacks resonance stabilization, so it is less acidic than ortho, while para is least acidic here due to relative stabilization differences and intramolecular effects in the ortho isomer.
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