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Sucrose in water is dextro-rotatory, [α]D = +66.4°. When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = -20°. In this process, the sucrose molecule breaks into

1. (a) L-glucose + D-fructose
2. (b) L-glucose + L-fructose
3. (c) D-glucose + D-fructose
4. (d) D-glucose + L-fructose

Correct answer: (c) D-glucose + D-fructose

Solution

Sucrose hydrolyzes into D-glucose and D-fructose in the presence of dilute HCl. The initial dextro-rotatory nature of sucrose changes to levo-rotatory due to the higher specific rotation of D-fructose (-92°) compared to D-glucose (+52.7°).

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