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Given reactions (white precipitate with H2S in presence of NH4OH) indicate that 'X' should be ZnCl2 which explains all given reactions.

1. ZnCl2 + 2H2O → Zn(OH)2 + 2HCl
2. Zn(OH)2 → Na2ZnO2 + 2H2O (Excess NaOH)
3. NH4OH + HCl → Dense white fumes
4. None of the above

Correct answer: ZnCl2 + 2H2O → Zn(OH)2 + 2HCl

Solution

The reaction of ZnCl2 with water forms Zn(OH)2, which is consistent with the given reactions involving white precipitate formation. This supports option A.

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