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For third ionization enthalpy electronic configuration of Mn is most stable due to half-filled d-orbital. Hence, 3rd ionization energy will be highest for Mn.

1. V³⁺ -> 4s⁰3d²
2. Cr²⁺ -> 4s⁰3d⁴
3. Mn²⁺ -> 4s⁰3d⁵
4. Fe²⁺ -> 4s⁰3d⁶

Correct answer: Mn²⁺ -> 4s⁰3d⁵

Solution

Mn²⁺ has a 4s⁰3d⁵ configuration, which is highly stable due to the half-filled d-orbital. Removing another electron (3rd ionization) requires significantly more energy, making its 3rd ionization enthalpy the highest.

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