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The correct order of decreasing second ionisation enthalpy of Ti (22), V (23), Cr (24) and Mn (25) is:

1. Cr > Mn > V > Ti
2. V > Mn > Cr > Ti
3. Mn > Cr > Ti > V
4. Ti > V > Cr > Mn

Correct answer: V > Mn > Cr > Ti

Solution

Second ionisation enthalpy depends on the electronic configuration after the removal of the first electron. V has a stable half-filled 3d3 configuration after losing one electron, making its second ionisation enthalpy higher than others. Mn, Cr, and Ti follow based on their configurations.

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