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Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po)?
- H2S < H2O < H2Se < H2Te < H2Po
- H2O < H2S < H2Se < H2Te < H2Po
- H2Po < H2Te < H2Se < H2S < H2O
- H2Se < H2Te < H2Po < H2O < H2S
Correct answer: H2Po < H2Te < H2Se < H2S < H2O
Solution
Thermal stability decreases down the group due to weaker E-H bond strength as atomic size increases. Hence, H2O is the most stable, and H2Po is the least stable.
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