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In water saturated air, the mole fraction of water vapour is 0.02. If the total pressure of the saturated air is 1.2 atm, the partial pressure of dry air is

1. 0.98 atm
2. 1.18 atm
3. 1.76 atm
4. 1.16 atm

Correct answer: 0.98 atm

Solution

The partial pressure of dry air is calculated by subtracting the partial pressure of water vapor from the total pressure. Since the mole fraction of water vapor is 0.02, its partial pressure is 0.02 × 1.2 atm = 0.024 atm. Thus, the partial pressure of dry air is 1.2 atm - 0.024 atm = 0.98 atm.

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