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Given nCO = nN2, PCO + PN2 = 1 atm. Partial pressure of a gas = mole fraction of gas × total pressure.

1. PN2 = nN2 / (nCO + nN2) × 1 = nN2 / 2nN2 × 1 = 1/2 = 0.5 atm.
2. P = nRT / V = wRT / mV = 6 × 8.314 × 402 / 16.05 × 0.03 = 41648 Pa.
3. At higher temperature and low pressure real gas acts as an ideal gas.
4. By Ideal gas equation.

Correct answer: At higher temperature and low pressure real gas acts as an ideal gas.

Solution

Option C is correct because real gases behave more like ideal gases at high temperatures and low pressures due to reduced intermolecular forces and increased kinetic energy.

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