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500 mL of nitrogen at 27°C is cooled to −5°C at the same pressure. The new volume becomes

1. 326.32 mL
2. 446.66 mL
3. 546.32 mL
4. 771.56 mL

Correct answer: 446.66 mL

Solution

Using Charles's Law (V1/T1 = V2/T2), convert temperatures to Kelvin: T1 = 300 K, T2 = 268 K. V2 = V1 × (T2/T1) = 500 × (268/300) = 446.66 mL.

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