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The volume occupied by 1.8 g of water vapour at 374°C and 1 bar pressure will be [Use R = 0.083 bar L K⁻¹ mol⁻¹]

1. 5.37 L
2. 96.66 L
3. 55.87 L
4. 3.10 L

Correct answer: 55.87 L

Solution

To calculate the volume, use the ideal gas equation PV = nRT. First, calculate moles of water: n = 1.8 g / 18 g/mol = 0.1 mol. Then, substitute into the equation: V = nRT / P = (0.1 mol × 0.083 bar L K⁻¹ mol⁻¹ × 647 K) / 1 bar = 55.87 L.

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