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Given initial volume (V₁) = 600 c.c.; Initial pressure (P₁) = 750 mm and final volume (V₂) = 500 c.c. According to Boyle's law, calculate the increase in pressure.

1. 750 × 600/500
2. 900 mm
3. 750 mm
4. 150 mm

Correct answer: 900 mm

Solution

Boyle's law states that P₁V₁ = P₂V₂. Substituting the given values, P₂ = (P₁V₁)/V₂ = (750 × 600)/500 = 900 mm. Thus, the increase in pressure is 900 mm - 750 mm = 150 mm.

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